Question

A cyclist travelling at 3.83 m/s [N] accelerates at a rate of 1.47 m/s2 [N] until he reaches a velocity of 13.88 m/s [N]. The time it takes the cyclist to reach their final velocity is ____________________ s. Record your answer to 2 decimal places.

Answer 1

Answer:

a = 6.84 ms^-2

Explanation:

Since, initial velocity=3.83 ms^-1

Since, final velocity = 13.88 m/s

Since, acceleration = 1.47 ms^-2

Therefore, v=u+at

=> 13.88 = 3.83+1.47a

=> a = 6.83673 ms^-2

=> a= 6.84 ms