A cyclist travels 1500 m from his house to his local shops in 300 seconds.
a) State the equation linking average speed, distance moved and time taken. b) Calculate the cyclist's average speed during his journey.
c) On the return home, the cyclist accelerates from 2.0 m/s with a steady acceleration of 2.4 m/s² Calculate the time it takes the cyclist to reach a speed of 10m/s.
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Answer: a) Average speed= total distance traveled = 1500 ms⁻¹ = 5ms⁻¹
total time taken 300
Distance moved= 1500m
Time taken= 300s= 5 min
b) Average speed= total distance traveled = 1500 ms⁻¹ = 5ms⁻¹
total time taken 300
c) a=2.4ms⁻²
v(final)=10ms⁻¹
u(initial)=20ms⁻¹
v= u + at
10= 20 + 2.4t
-10=2.4t
t= -10/2.4 = -10 x 10/24 =-4.1.
Since time can't be negative, it will be neglected. Thus, time taken to reach a speed of 10m/s is 4.1 seconds.
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Answer:
Explanation: average speed=total distance traveled1500ms=5ms
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