Physics, asked by anshubhadra35, 5 hours ago

) A cyclist travels 2km in first hour, 1.5km in second hour, 1km in third hour. Calculate the average speed of cyclist in km/h and m/s.​

Answers

Answered by geethikarkumar
1

Explanation:

Distance travelled in first hour = 1 km

Distance travelled in second hour = 0.5 km

Distance travelled in third hour = 0.3 km

Total time taken = 3 hr

Total distane travelled = 1+0.5+0.3=1.8 km =1800 m

1 hour =3600 seconds

3 hour =3600×3=10800 sec.

Average speed in ms

−1

=

Time

Distance

=

10800

1800

=0.167ms

Answered by sutariya10102007
0

Answer:

The average speed of the cyclist who travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour is 0.6 km/hr or 1/6 m/s.

Similar questions