Question

A cyclist travels a certain distance with a speed of 15km/h and returns with a speed of 10km/h. calculate the average speed of the whole journey i will mark as brainliest if answer first

Answer 1

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Given:

• Speed of cyclist while going = 15km/h
• Speed when returning = 10 km/h

To find:

• Average speed of total journey

Solution:

Using the formula

Average speed = 2V1V2/(V1 + V2)

Where

• V1 : speed while going
• V2 : speed while returning

Note : This information is only for this question

→ Avg speed = 2(15)(10)/15 + 10

→ Avg speed = 300/25

→ Average speed = 12 km/h

Hence , average speed = 12 km/h

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★ Knowledge enhancer :

1st kinematic equation : v = u + at

2nd kinematic equation : s = ut + 1/2 at²

3rd kinematic equation : v² - u² = 2as

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Answer 2

Answer:-

Given:-

• Initial speed (u) = 15 km/h
• Final speed (v) = 10 km/h

To Find:-

Average speed of the whole journey.

_________...

We know,

vₐᵥ = (v + u)/2

[Mean of the speeds]

where,

• vₐᵥ = Average speed,
• v = Final speed &
• u = Initial speed.

∴ vₐᵥ = [(10 + 15) km/h]/2

➵ vₐᵥ = (25 km/h)/2

➵ vₐᵥ = 12.5 km/h

∴ Average speed of the whole journey was 12.5 km h^-1.