Question

A cyclist travels a distance of 1.4 km in the first hour 0.25 km in the second hour and 0.15 km in the third hour, find the average speed in metre per second.​

Answer 1

Answer:

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Explanation:

Distance travelled in first hour = 1 km

Distance travelled in second hour = 0.5 km

Distance travelled in third hour = 0.3 km

Total time taken = 3 hr

Total distance travelled = 1 + 0.5 + 0.3 = 1.8 km

(i) Average speed in km h-1

Speed = Distance/Time taken = 1.8/3 = 0.6 km h-1

Average speed in m s-1

1 km = 1000 m

1.8 km = 1.8 × 1000 m

= 1800 m

1 hour = 3600 seconds

3 hour = 3600 × 3 = 10800 sec.

Average speed = D/T

=1800/10800 = 0.167 m s-1

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Answer 2

Given :

• Distance travlled by the cyclist in first hour = 1.4 km
• Distance travelled by the cyclist in second hour = 0.25 km
• Distance travelled by the cyclist in third hour = 0.15 km

To Find :

• The average speed of the cyclist in metres per second

Solution :

Total distance travelled by the cyclist = 1.4 km + 0.25 km + 0.15 km = 1.8 km = 1.8 × 1000 m = 1800 m

Total time taken = 3 hours = 3 × 3600 sec = 10,800 sec

Average speed is calculated by the ratio between total distance travelled to total time taken.

We have,

• Total distance travelled = 1800 m
• Total time taken = 10,800 sec

➙ Average speed = 1800 m/ 10800 sec

➙ Average speed = 0.16 m/s

Hence, the average speed of the cyclist in metres per sec is 0.16 m/s.