Physics, asked by 1259442, 11 months ago

A cyclist travels a distance of 1 km in the first hour , 0.5 km in the second hour and 0.3 km in the third hour . find the average speed of the cyclist in km/hr and m/sec

Answers

Answered by kushaldale
5

Explanation:

average speed = total distance travelled / time taken

= 1 + 0.5+ 0.3/3

= 1.8 /3

= 0.6 km/h

0.6 km/h = 0.6 ×1000/60×60

= 600/3600

= 0.17 or 0.16 m/s

Answered by Sejal005
8

Explanation:

Average speed = total distance

total time

so, T.dist. = 1+ 0.5+0.3

= 1.8 km

and , T. time = 3 hr

. therefore ,1.8/ 3

= 0.6 km/ hr

and in m/s =0.6 × 5/18

= 0.16 m/s

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