A cyclist travels a distance of 1 km in the first hour , 0.5 km in the second hour and 0.3 km in the third hour . find the average speed of the cyclist in km/hr and m/sec
Answers
Answered by
5
Explanation:
average speed = total distance travelled / time taken
= 1 + 0.5+ 0.3/3
= 1.8 /3
= 0.6 km/h
0.6 km/h = 0.6 ×1000/60×60
= 600/3600
= 0.17 or 0.16 m/s
Answered by
8
Explanation:
Average speed = total distance
total time
so, T.dist. = 1+ 0.5+0.3
= 1.8 km
and , T. time = 3 hr
. therefore ,1.8/ 3
= 0.6 km/ hr
and in m/s =0.6 × 5/18
= 0.16 m/s
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