A cyclist travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour. What is the average speed in (1) km/hr (2) m/sec ?
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2
Distance in one hour = 1 km
Distance in second hour = 0.5 km
Distance in third hour = 0.3 km
We know that,
Average speed = total distance /total time
i) Average speed in km/hr
ν = D/T
= 0.6km/hr
ii) Average speed in m/s
ν = 0.6* 5/8
= 0.167m/s
The average velocity is 0.6 km/hr and 0.167 m/s.
Answered by
1
Distance in one hour = 1 km
Distance in second hour = 0.5 km
Distance in third hour = 0.3 km
We know that,
Average speed = total distance /total time
i) Average speed in km/hr
ν = D/T
= 0.6km/hr
ii) Average speed in m/s
ν = 0.6* 5/8
= 0.167m/s
The average velocity is 0.6 km/hr and 0.167 m/s.
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