Question

A cyclist travels a distance of 1 km in the first hour ,0.5 km in the second hour and 0.3 km in the third hour. Find the average speed of the cyclist in (i) km h (ii) m s

Answer 1

we know that average speed =sum of speeds at different intervals / hours.
so,
$average \: speed = \frac{1 + 0.5 + 0.3}{3} \\ = \frac{1.8}{3} \\ = 0.6 \: kmph.$
PLZ MARK IT AS BRAINIEST ANSWER.

Answer 2

Answer: The average velocity is 0.6 km/hr and 0.167 m/s.

Explanation:

Given that,

Distance in one hour = 1 km

Distance in second hour = 0.5 km

Distance in third hour = 0.3 km

We know that,

Average speed = total distance /total time

(I). Average speed in km/hr

$v = \dfrac{D}{T}$

$v = \dfrac{1\ km+0.5\ km +0.3\ km}{3\ hr}$

$v = 0.6\ km/hr$

(II). Average speed in m/s

$v = 0.6\times\dfrac{5}{18}$

$v = 0.167\ m/s$

Hence, The average velocity is 0.6 km/hr and 0.167 m/s.