Question

a cyclist travels a distance of 4km from A to B then moves 3km towards right angle to AB. Find the resultant displacement and total distance covered.

Answer 1

Solution :

⏭ Given:

✏ A cyclist travels a distance of 4km from A to B then moves 3km towards right angle to AB.

⏭ To Find:

• Resultant displacement
• Total distance covered

⏭ Concept:

✏ Displacement is defined as the shortest distance between initial and final position of journey.

✏ Distance is defined as the actual length of path.

⏭ Calculation:

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• Distance travelled

$\implies \sf \: distance = AB + BC \\ \\ \implies \sf \: distance = 4 + 3 \\ \\ \implies \: \boxed{ \tt{ \red{distance = 7km}}}$

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• Displacement

$\implies \sf \: displacement = \sqrt{ {(AB)}^{2} + {(BC)}^{2} } \\ \\ \implies \sf \: displacement = \sqrt{ {4}^{2} + {3}^{2} } = \sqrt{16 + 9} \\ \\ \implies \sf \: displacement = \sqrt{25} \\ \\ \implies \: \boxed{ \tt{ \purple{displacement = 5km}}}$

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⏭ Additional information:

• Distance is scalar quantity.
• Displacement is vector quantity.

Answer 2

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Refer the attachment

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