Question

a cyclist travels a distance of 4km from p to qand then moves a distance of 3km at right angle to pq.find his resultant displacement graphically.

Answer 1

The resultant displacement of the cyclist is R = 5.

The given data states that the cyclist travel 4 km and then travels 3 km. These form a vector when represented graphically and are perpendicular to each other. Therefore the resultant displacement is calculated using vector addition rule.

The given vectors are PQ and QA, where PQ = 4 and QA = 3. Thereby, we have resultant displacement $\bold{R^{2}=P Q^{2}+Q A^{2}}$

$\begin{array}{l}{\Rightarrow \mathrm{R}=\sqrt{4^{2}+3^{2}}} \\ {\Rightarrow \mathrm{R}=\sqrt{16+9}} \\ {\Rightarrow \mathrm{R}=\sqrt{25}} \\ {\Rightarrow \mathrm{R}=5}\end{array}$.

Answer 2

Answer:

Resultant Displacement:5km

Explanation:

Given Data states that a cyclist travels 4km and then 3 km.These form a vector when represented graphically.

Using Vector Addition Rule

                 R^=PQ^+QA^

R^=4^+3^

R^=16+9

R^=25

R  =5