a cyclist travels a distance of 8 km from P to Q and then moves a distance of 6 km at right angle to PQ. calculate the 1) distance moved, 2) displacement of the cyclist .
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Answered by
10
DISTANCE MOVED = TOTAL LENGTH OF PATH TRAVELLED =(8 + 6)km = 14 km
BY APPLYING PYTHAGORAS THEOREM
DISPLACEMENT = x (let)
we get,
x^2= 8^2 + 6^2
equating we get
x^2 = 100
x=√100 =10
DISPLACEMENT= 10 km
BY APPLYING PYTHAGORAS THEOREM
DISPLACEMENT = x (let)
we get,
x^2= 8^2 + 6^2
equating we get
x^2 = 100
x=√100 =10
DISPLACEMENT= 10 km
priyankajoshi59:
tumhara displacement glt hai ye pythagoras th. se solve hoga aur acc. to that hypotnuse kbhi bhi perpendicular ya fr base se chota nhi hota hai
read the question
it is 8 not 18
oo i m sorry
its ok
Answered by
2
1) distance = PQ + QR
= 18+6
=24 km
2) displacement can be found by using pythagoras th.
h²=p²+ b²
h²=6² + 18²
h² = 36 + 324
h² = 360
h²=√360
h²=18.97
= 18+6
=24 km
2) displacement can be found by using pythagoras th.
h²=p²+ b²
h²=6² + 18²
h² = 36 + 324
h² = 360
h²=√360
h²=18.97
wrong
displacement is 10
yes
yes u r wright its wrong i m sorry
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