Question

a cyclist travels from center o of a circular path of radius 1km and reached points p. after cycling1_4th of the circumference long pq he returns to the centre of park qo if the total time taken is 10minate caculate average velocity of the cyclist​

Answer 1

Explanation:

(a) Displacement is given by the minimum distance between the initial and final positions of a body. In the given case, the cyclist comes to the starting point after cycling for 10 minutes. Hence, his net displacement is zero.

(b) Average velocity is given by the relation:

Average velocity = Net Displacement / Total time

Since the net displacement of the cyclist is zero, his average velocity will also be zero.

(c) Average speed of the cyclist is given by the relation:

Average speed = Total path length / Total time

Total path length = OP + PQ + QO

= 1 + (1 (2π × 1) / 4 ) + 1

= 2 + (π / 2)

= 3.570 km

Time taken = 10 min = 10 / 60 = 1 / 6 h

∴ Average speed = 3.570 / (1/6) = 21.42 km/h