Question

A cyclist wants to loop the loop the death globe of diameter 5m. Find the minimum velocity, that he should have at lowest point and calculate the height from which he should start it. (g=10m/s^2)​

Answer 1

Answer:

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Answer 2

The height from which he should start it is 6.25m.

Potential energy, mgh of the body equals to the kinetic energy (1/2 mv²).

So, mgh = (1/2) mv².

where, m is the mass,

v is the velocity of cyclist,

g is acceleration due to gravity.

Cancelling m from both sides, we get:

gh = (1/2)v².

⇒v = √(2gh)

Again,in the globe of death minimum velocity required to loop = √(5gr)

r is the radius of globe,

As both the velocities are equal,

√(2gh) = √(5gr)

Squaring both sides,

2gh = 5gr.

⇒ h = 5r/2

Diameter = 5m, so radius = diameter/2 = 5m/2 = 2.5m

So, height from which it shoulf start is

h = (5×2.5)/2 = 6.25m.