A cyclist was moving at a speed of 5m/sec and picks up a speed of 10m/sec in a distance of 50 m what is its acceleration?
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Answered by
3
v2-u2=2as
100-25=2*a*50
75=100a
a=3÷4=0.75m per second sq.
100-25=2*a*50
75=100a
a=3÷4=0.75m per second sq.
Answered by
1
U= 5m/s
V=10m/s
S=50m
We know,
2as=v^2-u^2
A=(10×10)-(5×5)/2×50
A=75/100
A=0.75m/s2
We know
A=v-u/t
75/100×t=10-5
T=3.75 seconds
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