Question

A cyclist while negotiating a circular path with speed 20 m / s is found to bend an angle by 30 degree with vertical. What is the madius of the circular path?​

Answer 1

Answer:

Balancing the forces:

Nsin30°=mg⟶(1)

and

Ncos30°=

R

mv

2

⟶(2)

dividing (2) by (1)

tan30°=

v

2

gR

⇒v

2

=

tan30°

gR

⇒v

2

=10×20

3

×

3

=200×3=600

v=

600

=24.5m/s

=14

3

m/s