Question

A cyclist while negotiating a circular path with speed 20ms-1 is found to bend an angle by 30° with vertical .What is the radius of the circular pah? (Assume g=10 ms -2 )7

Answer 1

Answer:

Explanation:

V=20 ms-1

Angle=30

g=10

tan(angle)=v^2/rg

1/root3=400/r*10

r=40 root 3 m

Answer 2

Answer:

The radius of the circular path is 69.28m.

Explanation:

We will use the following formula to solve this question,

$tan\theta=\frac{v^2}{rg}$     (1)

Where,

θ=angle made by the cyclist with the vertical

v=velocity with which the cyclist is moving

r=radius of the circular path

g=acceleration due to gravity

From the question we get;

v=20m/s

θ=30°

g=10m/s²

By substituting the values of v,θ, and g in equation (1) we get;

$tan30\textdegree=\frac{(20)^2}{r\times 10}$

$r=\frac{400\times \sqrt{3} }{10}$

$r=69.28m$

Hence, the radius of the circular path is 69.28m.