Math, asked by gaurav200268, 1 year ago

a cylinder container of radius 42cm and height 90cm is filled with ice cream up to 80% of its capacity how many cone can we fill witb ice cream of radius 7 cm and height 10 cm
please answer this fast​

Answers

Answered by rizwan1
3

Volume of cylinder= l×b×h= pi× r2 ×h

22/7× 42×90=11880

But in question tank filled with 80/100 ×11880=9504 cm3

Volume of icecream" cone"= 1/3pi r2h

1/3 ×22/7×49×10=513

SO NO OF CONES= 9504/513=18



Answered by Anonymous
7

given :-

radius of the cylindrical container = 42cm

height of the cylindrical container = 90cm

➡ it's volume = πr²h

= 22/7 × 42 × 42 × 90

= 22 × 6 × 42 × 90

= 498960cm³

ATQ, ice cream in the container is filled up to 80%

➡ 498960 × 80/100

➡ 399168cm³

volume of the cone = 1/3πr²h

given radius and height of the cone 7cm and 10cm Respectively.

= 1/3 × 22/7 × 7 × 7 × 10

= 1540/3cm³

therefore no. of cones can be filled with the ice cream = 399168/1 × 3/1540

= 259.2 × 3

= 777.6

hence, 777 cones can be filled with icecream.

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