Question

A cylinder containing a vaccine is dropped from a helicopter hovering at
a height of 200 m above the ground. The acceleration due to gravity is
10 m/s2. Calculate the speed at which the cylinder will hit the ground.
You are given the acceleration, a = 10 m/s2, and the distance, s = 200 m.
through which the cylinder moves. The initial velocity, u, is not stated, but
you assume it is O m/s as the helicopter is hovering (staying in one place in
the air). Substitute these values in the given equation:
v2 = U2 + 2as
= 0 m/s2 + (2 x 10 m/s2 x 200 m)
= 4000 m/s2
therefore v = (4000 m/s2
= 63.25 m/s​

Answer 1

Answer:

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Answer 2

How did you get 63.25 m/s?