Question

a cylinder containing water stands on table of height h . a small hole is punched in the side of cylinder at its horizontal distance r from the table .then, the depth of water in cylinder is

Answer 1

Solution :

Let t is time taken by the jet to travel the vertical height H from bottom of the cylinder and v is the velocity of stream of water,

H=1/2gt^2------------1

t=(2H/g)^1/2-------------2

v=(2gh)^1/2-----------3

The horizontal distance R travelled by stream=vt=[(2gh)^1/2][(2H/g)^1/2]----------------4

solving equation 4, we get h(depth of water in the cylinder)=R^2/4H(ans)

Answer 2

I hope this will help you