Math, asked by Shambhavpandey4538, 1 year ago

A cylinder garden roller is 75 cm long and it's radius is 14 cm. How many revolutions will it make to level an area of 9900 cm square.

Answers

Answered by 1234amartyanjan
37

Answer:

Step-by-step explanation:

height of cylindrical pillar = 75 cm

radius of cylindrical pillar = 14 cm

CSA of cylindrical pillar =  2pirl

                                         = 2*22/7*14*75

                                           = 150*44

                                            = 6600 cm

area to be covered = 9900 cm

no. of revolution required = 9900/6600

                                           =3/2 revolutions

                                               

                                   

Answered by Anonymous
17

curved surface area of cylinder=2πrh

=>2×22/7×14cm×75cm

=>88cm×75cm

revolutions it will take=total area of ground/curved surface area of cylinder

=>9900cm²/88cm×75cm

=>1.5

hence 1.5 revolution it will take

hope it helps you mate

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