Question

A cylinder has a base area of 64π m2. Its height is equal to twice the radius. Identify the volume of the cylinder to the nearest tenth.
V = 1402.1 m3
V = 2804.2 m3
V = 6434.0 m3
V = 3217.0 m3

Answer 1

Answer:

base area πr²=64πm²

so r=8m

h=2r=2(8)=16m

volume=πr²h

=(22×64×16)/7

=3218.2m³

it is approximately 3217.0m³

Answer 2

Answer:

• 3215 .36 m³ is the required volume.

Step-by-step explanation:

• Base area of Cylinder = 64π m²
• Height of cylinder is equal to twice the radius .

As we know that ,

★Base Area of Cylinder = πr²

where,

• π is taken as 22/7 or 3.14
• r is the radius of cylinder

Substitute the value we get

↝ 64 π = πr²

↝ 64 = r²

↝ √64 = r

↝ 8 = r

↝ r = 8 m

Now, it is given that height is equal to twice of radius

Therefore ,

height = 2r = 2×8 = 16 m

★Volume of Cylinder = πr²h

substitute the value we get

↝ volume of Cylinder = 3.14 × 8² × 16

↝volume of Cylinder = 3.14 × 64 × 16

↝volume of Cylinder = 3215 .36 m²

• Hence, the required volume of cylinder is 3215 .36 m³.