A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (Use 3.14 as an approximation of .)
Answers
Answered by
2
PIE R^2 H =CYLINDER'S VOLUME
3.14*5^2*16=1256 CM^3
1/3 PIE R^2 H=CONE'S VOLUME
1/3*3.14*16*12=200.96 CM^3
1256-200.96=1055.04 CM^3
THEREFORE,THE AIR SPACE SURROUNDING THE CONE INSIDE THE CYLINDER IS 1055.04 CM^3
3.14*5^2*16=1256 CM^3
1/3 PIE R^2 H=CONE'S VOLUME
1/3*3.14*16*12=200.96 CM^3
1256-200.96=1055.04 CM^3
THEREFORE,THE AIR SPACE SURROUNDING THE CONE INSIDE THE CYLINDER IS 1055.04 CM^3
Answered by
2
hope its help u bro
Attachments:
Similar questions