A cylinder having diameter 40cm and height 70cm and contain 4 by 5th of water .If the cone having some diameter and height equal to 4by 3 times the height of the Cylinder ,how much water flow throw from vessel?
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photo not clearly but ans is 50 i think
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nAshu111:
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Answer:
Step-by-step explanation:
Here, diameter =40 cm
R=d/2=40/2=20 cm
H=70 cm
The volume of cylinder (the volume of water)
=pie×r square ×h
22/7 ×20×20×7
=88000cm cube
The water is up to 4/5th of the cylinder.
1/5th of the cylinder is without water
88000×1/5=17600cm cube of water is added to the cylinder to make it full of water.....eqn 1
For cone,
R=18 cm
H=3/4×70=52.5 cm
Volume of cone =1 /3 x pie x r Sq. x h
=1/3×22/7×18×18×52.5
=17820 cm cube........ Eqn 2
The water overflowing =17820 - 17600...... From eqn 1 and 2
=220 cm cube
220 cm cube of water will over flow
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