Question

a cylinder is 42 cm long and its diameter from exterior is 16 cm. if the weight ot it is 16g/cm3 and thickness is 2 cm, then find the weight of cylinder ​

Answer 1

FINAL ANSWER:-

$59196cm^{3}$

or

59196 kg

GIVEN:-

h=42 cm

r1=$\frac{16}{2}=8 cm$

r2=$\frac{16-2-2}{2}=6 cm$

FORMULA USED:-

πhr²1-πhr²2      or     πh(r²1-r²2)       [Volume of cone]

SOLUTION:-

volume of hollow cylinder = πhr²1-πhr²2 OR  πh(r²1-r²2)

                                            =$\frac{22}{7}*42(8^{2}-6^{2})$

                                            =$\frac{22}{7}*42(64-36)$

                                            =$\frac{22}{7}*42*28$

                                            =$22*6*28$

                                            =3696 cm³

∴ weight of cylinder = 3696 cm³ × 16cm³

                                 = 59.196 kg

Answer 2

mainhununknown ne sahi answer diya hai toh use brainlist bana do