A cylinder is open at one end. The external diameter is 10 cm and thickness 2 cm if the height is 8 cm (a) capacity of cylinder (b) volume of metal used.
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Answered by
47
Given:-
- Height = 8cm
- external diameter= 10cm
- external Radius= 10/2
= 5cm
Thickness= 2cm
Internal Radius = External Radius - Thickness
= 5cm - 2cm
= 3cm
Solution:-
(a) Capacity of cylinder (Radius used here is Internal radius)
→ π × r² × h
→ π × 3² × 8
→ π × 9 × 8
→ π × 72cm²
=>226cm³
Entire cylinder's volume - internal cylinder's volume = external cylinders volume
volume of metal used = external cylinder's volume
entire cylinder's volume
→ π × R²×h
→ π × 5² ×8
→ π × 25 × 8
→ π ×200cm²
=> 628cm³
Volume of Internal cylinder
226cm³
(b) Volume of metal used
External volume - Internal volume = Volume of. metal used
628 - 226
402cm³
Ans (a) 226cm³ (b) 402cm³
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Answered by
4
Answer:
(a)226.28cm^3
(b)402.28cm^3
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