A cylinder is open at one end. The external diameter is 10 cm and thickness 2 cm if the height is 8cm (a) capacity of cylinder (b) volume of metal used.
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Answer:
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Step-by-step explanation:
h (height) = 8 cm
De (external diameter) = 10 cm
radius (external diameter)
De = 2*r → 2r = D → r = De/2 → r = 10/2 → r (radius) = 5 cm
di (internal diameter) = ?
th (thickness) = 2 cm
Total Volume of cylinder:
π r^2 h = 3.14 * 8 * 5^2
V = 628 cm^3
External diameter = internal diameter + 2 * thickness
10 = i.d + 2 * 2
i.d = 10 - 4
= 6 cm
radius (internal diameter)
Di = 2*r → 2r = Di → r = Di/2 → r = 6/2 → r (radius) = 3 cm
To find the capacity of the cylinder, we subtract the total volume value of the cylinder minus the volume value of the metal
Find capacity of cylinder: (internal volume)
V = 628 - 226.08
V = 401.92 cm^3
Volume of metal used:
h * π * r^2
= 8 * 3.14 * 3^2
= 266.08 cm^3
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