A cylinder is open at one end. The external diameter is 15cm and its thickness is 3 cm. If the height of the cylinder is 11 cm and 1 qubic cm is 9 gm, find (i) THE CAPACITY OF THE CYLINDER. (ii) WEIGHT OF THE METAL USED IN THE CYLINDER. (π= 3.14)
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Answer:
R = 7.5cm
r = 4.5cm
h=11cm
capacity= πr 2h=3.14x4.5^2 x 11
= 699.435cm3. Ans:
Weight of metal:=Volx9
Vol:
= πh (R+r) (R-r) +πR^h
= πx11 (7.5+4.5) 3+πx7.5^2 x3
= πx11 x 12x3 +168.75π
=396 π +168.75π = 564.75πcm3
= 1773.315cm3.
Weight of metal=1773.315x9
=15959.8358=15.960kg Ans
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