Math, asked by ans81, 1 year ago

a cylinder kal roller of length 2.5 M and diameter 3M when rolled on a road was found to cover the area of 33000 M sq how many revolutions did it make

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Answers

Answered by sonabrainly

Hi there !!

The length of the cylindrical pipe is the same as its height.

h = 2.5 m

r = 1.75 m

Total area covered = 5500 m²

Area covered by 1 revolution = C.S.A of the pipe

= 2πrh

= 2 × 22/7 × 1.75 × 2.5

= 27.5 m²

No : of revolutions made = Total area covered ÷ C.S.A

= 5500 ÷ 27.5

= 200 revolutions

Answered by legendarysumit

h=2.5
r,=1 .75
total area equal to 5500 m square
area of one revolution=C.S .Aof the pipe
=2πrh
=2×22/7×1.75*2.5
=27.5m²

the revolution did it make
5500/27.5=200revolution

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