Question

A cylinder of curved surface area 1,250m^2 is formed from a rectangular metallic sheet find the dimesions of the rectangular sheet if its length is doubled its breadth

Answer 1

$\purple{\underline{Hey mate !}}$

A cylinder of C.S.A 1250 m² is formed from a rectangular metallic sheets

Breadth of sheet = x

Length of sheet = 2x

Area of rectangular sheet = length × Breadth

$\boxed{\green{CSA \:=\: 2\pi r\times h}}$

where

2πr is a length

h is a breadth of rectangle

therefore,

Length of sheet × Breadth of sheet= 1250

2x.x = 1250

2x² = 1250

x = √ 625

x = 25 cm

$\boxed{\pink{Breadth \:of\: sheet \:= \:x \:= \:25 \:cm}}$

$\boxed{\orange{Length \:of \:sheet\: = \:2x\: = \:25 \:× \:2 \:= \:50 \:cm}}$

Answer 2

Hello!

$\underline{\sf Let}$ :

• Breadth be $\bf{x}$
• Length be $\bf{2x}$

Then,

$\boxed{\sf Area = \sf 1250\: m^{2}}$

⇒ l × b = 1250 m²

⇒ 2x (x) = 1250

⇒ 2x² = 1250

⇒ x² = $\dfrac{\sf 1250}{\sf 2}$

⇒ x = $\sqrt{625}$ ⇒ ± $\bf{25}$

Hence,
• Breadth = $\textcolor{Blue}{\bf{25\:m}}$
• Length, l = 25(2) = $\textcolor{Blue}{\bf{50\:m}}$

Cheers!