Question

a cylinder of curved surface area 1250 m square is formed from a rectangular metallic sheet. find the dimensions of the rectangle sheet if its length is double its breadth

Answer 1

first let the length be 2x
and breadth be x
now both figures have same area
so, 2X×X=1250
2Xsquare=1250
Xsquare=1250/2=625
X=
$\sqrt{625}$
X=25
then put the value of X in length and breadth
length =50m, breadth =25m
hope it will help you

Answer 2

Given :
Curved Surface Area (CSA) = 1250m²

According to the question,
The cylinder is formed into a rectangular metallic sheet.

Also,
given : The length of the rectangular sheet is double its breadth.

Let,
breadth be $\bf{b}$ m
length = $\bf{2b}$ m


So,
$\bf{Area\: of\: the\: rectangular\: sheet = CSA\: of \:cylinder }$

=> length × breadth = 1250

=> $\bf{2b}$×$\bf{b}$ = 1250

=> $\bf{2b}$² = 1250

=> $\bf{b}$² = $\frac{1250}{2}$

=> $\bf{b}$² = 625

=> $\bf{b}$ = $\sqrt{625}$

=> $\bf{b}$ = 25

Therefore, breadth ($\bf{b}$) = 25 m,
and length = 2b = 2×25 = 50 m