Question

A cylinder of fixed
capacity 67.2 litres
contains helium gas at
STP. Calculate the
amount of heat required
to raise the temperature
of the gas by
15°C?(R = 8.314 J mol'k-')​

Answer 1

Answer:

$<svg id="wrap" width="300" height="300"></p><p></p><p><!-- background --></p><p></p><p><svg></p><p></p><p><circle cx="150" cy="150" r="130" style="stroke: lightblue; stroke-width:18; fill:transparent"/></p><p></p><p><circle cx="150" cy="150" r="115" style="fill:#2c3e50"/></p><p></p><p><path style="stroke: #2c3e50; stroke-dasharray:820; stroke-dashoffset:820; stroke-width:18; fill:transparent" d="M150,150 m0,-130 a 130,130 0 0,1 0,260 a 130,130 0 0,1 0,-260"></p><p></p><p><animate attributeName="stroke-dashoffset" dur="6s" to="-820" repeatCount="indefinite"/></p><p></p><p></path></p><p></p><p></svg></p><p></p><p><!-- image --></p><p></p><p><svg></p><p></p><p><path id="hourglass" d="M150,150 C60,85 240,85 150,150 C60,215 240,215 150,150 Z" style="stroke: white; stroke-width:5; fill:white;" /></p><p></p><p><path id="frame" d="M100,97 L200, 97 M100,203 L200,203 M110,97 L110,142 M110,158 L110,200 M190,97 L190,142 M190,158 L190,200 M110,150 L110,150 M190,150 L190,150" style="stroke:lightblue; stroke-width:6; stroke-linecap:round" /></p><p></p><p><animateTransform xlink:href="#frame" attributeName="transform" type="rotate" begin="0s" dur="3s" values="0 150 150; 0 150 150; 180 150 150" keyTimes="0; 0.8; 1" repeatCount="indefinite" /></p><p></p><p><animateTransform xlink:href="#hourglass" attributeName="transform" type="rotate" begin="0s" dur="3s" values="0 150 150; 0 150 150; 180 150 150" keyTimes="0; 0.8; 1" repeatCount="indefinite" /></p><p></p><p></svg></p><p></p><p><!-- sand --></p><p></p><p><svg></p><p></p><p><!-- upper part --></p><p></p><p><polygon id="upper" points="120,125 180,125 150,147" style="fill:#2c3e50;"></p><p></p><p><animate attributeName="points" dur="3s" keyTimes="0; 0.8; 1" values="120,125 180,125 150,147; 150,150 150,150 150,150; 150,150 150,150 150,150" repeatCount="indefinite"/></p><p></p><p></polygon></p><p></p><p><!-- falling sand --></p><p></p><p><path id="line" stroke-linecap="round" stroke-dasharray="1,4" stroke-dashoffset="200.00" stroke="#2c3e50" stroke-width="2" d="M150,150 L150,198"></p><p></p><p><!-- running sand --></p><p></p><p><animate attributeName="stroke-dashoffset" dur="3s" to="1.00" repeatCount="indefinite"/></p><p></p><p><!-- emptied upper --></p><p></p><p><animate attributeName="d" dur="3s" to="M150,195 L150,195" values="M150,150 L150,198; M150,150 L150,198; M150,198 L150,198; M150,195 L150,195" keyTimes="0; 0.65; 0.9; 1" repeatCount="indefinite"/></p><p></p><p><!-- last drop --></p><p></p><p><animate attributeName="stroke" dur="3s" keyTimes="0; 0.65; 0.8; 1" values="#2c3e50;#2c3e50;transparent;transparent" to="transparent" repeatCount="indefinite"/></p><p></p><p></path></p><p></p><p><!-- lower part --></p><p></p><p><g id="lower"></p><p></p><p><path d="M150,180 L180,190 A28,10 0 1,1 120,190 L150,180 Z" style="stroke: transparent; stroke-width:5; fill:#2c3e50;"></p><p></p><p><animateTransform attributeName="transform" type="translate" keyTimes="0; 0.65; 1" values="0 15; 0 0; 0 0" dur="3s" repeatCount="indefinite" /></p><p></p><p></path></p><p></p><p><animateTransform xlink:href="#lower" attributeName="transform"</p><p></p><p>type="rotate"</p><p></p><p>begin="0s" dur="3s"</p><p></p><p>values="0 150 150; 0 150 150; 180 150 150"</p><p></p><p>keyTimes="0; 0.8; 1"</p><p></p><p>repeatCount="indefinite"/></p><p></p><p></g></p><p></p><p><!-- lower overlay - hourglass --></p><p></p><p><path d="M150,150 C60,85 240,85 150,150 C60,215 240,215 150,150 Z" style="stroke: white; stroke-width:5; fill:transparent;"></p><p></p><p><animateTransform attributeName="transform"</p><p></p><p>type="rotate"</p><p></p><p>begin="0s" dur="3s"</p><p></p><p>values="0 150 150; 0 150 150; 180 150 150"</p><p></p><p>keyTimes="0; 0.8; 1"</p><p></p><p>repeatCount="indefinite"/></p><p></p><p></path></p><p></p><p><!-- lower overlay - frame --></p><p></p><p><path id="frame" d="M100,97 L200, 97 M100,203 L200,203" style="stroke:lightblue; stroke-width:6; stroke-linecap:round"></p><p></p><p><animateTransform attributeName="transform"</p><p></p><p>type="rotate"</p><p></p><p>begin="0s" dur="3s"</p><p></p><p>values="0 150 150; 0 150 150; 180 150 150"</p><p></p><p>keyTimes="0; 0.8; 1"</p><p></p><p>repeatCount="indefinite"/></p><p></p><p></path></p><p></p><p></svg></p><p></p><p></svg>$

Answer 2

ANSWER:

561.2 J

Step-by-step explanation:

 For 1 mole of an ideal gas → 22.4 L volume acquired

 then for 3 moles → 67.2 L volume

then according to the formula...

Q=n×Cv×ΔT

n = 3 moles

Cv = 3/2 R (gas constant)

ΔT = 15°C

∴ Q = 3×3÷2 ×R ×15

∴Q = 4.5×R×15

∴Q = 4.5 * 8.314 * 15

∴Q = 561.195 J

approximately 561.2 J