Math, asked by pk6251, 1 year ago

A cylinder of height 8 cm and radius 3.5 cm is perfectly put inside of another cylinder with their axis perpendicular to each other. Whats the radius of other cylinder.


kmahadeva1991p4qz0h: Please give full solution.

Answers

Answered by rutvikjadav13p4chyz
3
use pythagoras theorem with height and diameter (which is given)



u wil get the diameter of large cylinder 

ans is radius = (root113)/2
Answered by RenatoMattice
0

Answer: Radius of other cylinder is 5.32 cm.

Step-by-step explanation:

Since we have given that

Height of a cylinder (h) = 8 cm

Radius of a cylinder = 3.5 cm

Diameter of cylinder (d) is given by

3.5\times 2=7\ cm

Since we have also given that it is perfectly put inside of another cylinder with their axis perpendicular to each other.

According to figure shown below:

so, Diameter of other cylinder = Diagonal of cylinder

As we know the formula for "Diagonal of cylinder"

Diagonal=\sqrt{d^2+h^2}\\\\Diagonal=\sqrt{7^2+8^2}\\\\Diagonal=\sqrt{49+64}\\\\Diagonal=\sqrt{113}\\\\Diagonal=10.63

So, Diameter of other cylinder = 10.63 cm

Radius of other cylinder is given by

\frac{10.63}{2}=5.32\ cm

Hence, radius of other cylinder is 5.32 cm.

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