Math, asked by joel4545, 9 months ago

A cylinder of height 'H and radius of cross-section 'R is kept in uniform electric field E as shown in figure.
The magnitude of flux that enters from left half of cylinder is
(1) E.piR2
(3) E2RH
(2) E.RH
(4) Zero

Answers

Answered by chandrashilachaudhar

12

Answer:

cylinder on the height is to long = E2RH

Answered by gunjanagarwal260804

0

Answer:

E2RH

because flux=projected area*electric field=E.A

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