A cylinder of large length carries a charge of 2×10^8 C/m . Find the electric field at a distance of 0.2m from it.
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26
Answer:
Formula of the electric field (E) = kQ/r2
where k is a constant with a value of 8.99 x 10^9 N m2/C2
Data: Charge (Q) = 2×10^8 C/m
Distance (r)= 0.2m
Solution: E = kQ/r2
= 8.99 x 10^9 N m2/C2 x 2×10^8 C/m / (0.2m)
= 17.98 x10^17/0.04
= 4.495 x 10^19 NC-1m-1
Krishna12343:
Thanks
Answered by
2
Answer:
Explanation:
E = kQ/r2
= 8.99 x 10^9 N m2/C2 x 2×10^8 C/m / (0.2m)
= 17.98 x10^17/0.04
= 4.495 x 10^19 NC-1m-1
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