Physics, asked by nancybansal680, 10 months ago

A cylinder of large length carries a charge of 2×10^8 C/m . Find the electric field at a distance of 0.2m from it. ​

Answers

Answered by wajahatkincsem
26

Answer:

Formula of the electric field (E) = kQ/r2

where k is a constant with a value of 8.99 x 10^9 N m2/C2

Data: Charge (Q) = 2×10^8 C/m

         Distance (r)= 0.2m

Solution:  E = kQ/r2

                   = 8.99 x 10^9 N m2/C2 x 2×10^8 C/m  / (0.2m)

                   = 17.98 x10^17/0.04

                   = 4.495 x 10^19 NC-1m-1


Krishna12343: Thanks
Answered by utsavrajput777
2

Answer:

Explanation:

E = kQ/r2

                  = 8.99 x 10^9 N m2/C2 x 2×10^8 C/m  / (0.2m)

                  = 17.98 x10^17/0.04

                  = 4.495 x 10^19 NC-1m-1

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