Physics, asked by tezzzz30, 1 year ago

a cylinder of mass 10 gram weights 7 grams in water. if the area of cross section is 0.75m^2, its length is .

Answers

Answered by Infinitus
2
Mass of water displaced =3gms=3/10³kg



Mass=density(of water) *volume(of cylinder)


3/10³=10³kg/m³ *(area of cross -section*height)


Height=3/(10³*area of cross section)



Height=0.004metres. Or 0.4cm


tezzzz30: but the ans is 4 cm
Infinitus: Sorry to disappoint you
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