A cylinder of mass 30 kg and radius 2 meters is rolling on a table without sliding. If its velocity is 4 meters per second then calculate its kinetic energy.
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The kinetic energy of a rolling object is calculated like so:
KE=12mv2+12Iω2KE=12mv2+12Iω2
where mm is the mass, vv is the velocity, II is the moment of inertia of the object, and ωω is its angular velocity.
The first term is easy: we know the mass and velocity, so we just plug them in. To calculate the second term we would seem to need to know the radius of the cylinder. I mean, for a cylinder:
I=12mr2I=12mr2
and we can calculate the angular velocity from v and r:
ω=vrω=vr
Puzzling, but that makes the second term:
12Iω2=1212mr2(vr)212Iω2=1212mr2(vr)2
=14mr2v2r2=14mr2v2r2
and the r-squared terms cancel out, leaving
= 14mv214mv2
So the total answer is:
KE = 12mv2+14mv2=34
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