Question

A cylinder of mass 5 kg and radius 10 cm is moving on a horizontal surface with speed 5 m/s and
angular speed about C.M. is 10 rad/s. The angular momentum of the cylinder about point of contact​

Answer 1

Answer:

0.005

Explanation:

angular momentum= MoI*ω

                                =(\frac{MR^2}/{2})(10)

                                =5 x 0.01 x 0.01 x 10

                                =0.005