Question

A cylinder of radius 12 em contains water to
the height of 20 cm. A spherical iron ball is
dropped into the cylinder and thus water level is
raised by 6.75 cm. What is the radius of the ball?
HOTS​

Answer 1

Answer:

Let r be the radius of spherical ball.

when spherical ball is dropped into the tub, the level of water is raised by 6.75cm.

volume of spherical ball= volume of water displaced in the cylindrical tub

4/3 π r^3 = πR^2h

r^3 = 3/4×12×12×6.75

r^3 = 729 cm^3

r = 9 cm

:. Hence, the radius of the ball is 9 cm.