A cylinder of radius 12 em contains water to
the height of 20 cm. A spherical iron ball is
dropped into the cylinder and thus water level is
raised by 6.75 cm. What is the radius of the ball?
HOTS
Answers
Answered by
10
Answer:
Let r be the radius of spherical ball.
when spherical ball is dropped into the tub, the level of water is raised by 6.75cm.
volume of spherical ball= volume of water displaced in the cylindrical tub
4/3 π r^3 = πR^2h
r^3 = 3/4×12×12×6.75
r^3 = 729 cm^3
r = 9 cm
:. Hence, the radius of the ball is 9 cm.
Similar questions