A cylinder of radius 12cm contains water to a depth of 20cm. A spherical iron ball dropped into the cylinder and thus the water level is raised by 6.75 CM. Find the radius of the ball.
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Answered by
517
Solution:-
Radius of the cylinder = 12 cm
Height of the cylinder = 6.75 cm
Let 'r' be the radius of the spherical iron ball.
Volume of the cylinder = volume of the spherical iron ball
πr²h = 4/3πr³
22/7*12*12*6.75 = 4/3*22/7*r³
3 × 12 × 12 × 6.75 = 4r³
2916 = 4r³
r³ = 2916/4
r³ = 729
r = 9 cm
So, the radius of the spherical iron ball is 9 cm.
Answer
Radius of the cylinder = 12 cm
Height of the cylinder = 6.75 cm
Let 'r' be the radius of the spherical iron ball.
Volume of the cylinder = volume of the spherical iron ball
πr²h = 4/3πr³
22/7*12*12*6.75 = 4/3*22/7*r³
3 × 12 × 12 × 6.75 = 4r³
2916 = 4r³
r³ = 2916/4
r³ = 729
r = 9 cm
So, the radius of the spherical iron ball is 9 cm.
Answer
Answered by
25
Step-by-step explanation:
R = 9cm is the answer OK ok ok
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