A cylinder of radius R and length l is placed in a uniform electric field E parallel to the axis of the cylinder. The total flux over the curved surface of the cylinder is(a) zero(b) πR²E(c) 2πR²E(d) 
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Answered by
30
Answer:
a) Zero
Explanation:
Electric field E through any area A -
Ф = E.A = EA cos θ
S.I unit - volt(m) or N-m²/c
where -
Flux through surface ФA = E×πR² and ФB = E×πR²
Flux through curved surface C = ∫ Eds = ∫ Eds cos 90° = 0
Therefore total flux through cylinder = ФA+ФB+ФC = 0
Thus, the total flux over curved surface of cylinder is zero
aalindrisas:
Ummm. when the cylinder is placed parallel to the electric field, how is the E through the curved surface zero. Cos theta will be one since the angle between area vector and electric field will be zero
Answered by
7
Explanation:
Flux through surface A,
ϕ
A
=E×πR
2
ϕ
B
=−E×πR
2
Flux through curved surface, C=∫E.ds
=∫Edscos90
o
=0
∴ Total flux through cylinder =ϕ
A
+ϕ
B
+ϕ
C
=0
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