Question

A cylinder of wood floats vertically in water with one-fourth of its length out of water. The density of wood
is:
(A) 0.5 g/an
(B) 0.5 g/cm
(C) 0.75 g/cm
(D) 1 g/cm​

Answer 1

Answer:

b)o.5 g/cm because according to question one _fourth of its length is out of water

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Answer 2

The density of wood is $0.75\ g/cm^3$

(C) is correct option.

Explanation:

Given that,

A cylinder of wood floats vertically in water with one-fourth of its length out of water.

We need to calculate the density of wood

Using buoyancy force

$F_{b}=F_{w}$

$\rho_{wood}\times g\times V_{wood}=\rho_{w}\times g\timesV_{w}$

$\rho_{wood}=\dfrac{\rho_{water}\times\pi\times r^2\times\dfrac{3h}{4}}{\pi\times r^2\times h}$

$\rho_{wood}=\dfrac{1000\times3}{4}$

$\rho_{wood}=750\ kg/m^3$

$\rho_{wood}=0.75\ g/cm^3$

Hence, The density of wood is $0.75\ g/cm^3$

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Topic : density

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