a cylinder radius 28 metre and total surface area 5805 m^2 find height and lateral surface area
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T.S.A = 5805 m^2
Radius = 28 m(r)
Therefore 2pi * r( h+r) = 5805 m
56 * 3.14(h+28)= 5805
Therefore, 176 (h+28)=5805
176h = 5805 - 176*28 = 5805- 4928
H= (5805-4928)/176
h= 877/176 which is nearly equal to 5m
Therefore the answer for the first bit is 5m
Lateral surface area is given by the formula 2pi * r * h
=6.28 *28*5 = 879.2 m^2 ( approximately)
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Radius = 28 m(r)
Therefore 2pi * r( h+r) = 5805 m
56 * 3.14(h+28)= 5805
Therefore, 176 (h+28)=5805
176h = 5805 - 176*28 = 5805- 4928
H= (5805-4928)/176
h= 877/176 which is nearly equal to 5m
Therefore the answer for the first bit is 5m
Lateral surface area is given by the formula 2pi * r * h
=6.28 *28*5 = 879.2 m^2 ( approximately)
Please mark as brainliest answer
Thank you
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