Question

A cylinder rolls down an inclined plane of inclination 30°, the acceleration of cylinder is(a) $\frac{g}{3}$(b) g(c) $\frac{g}{2}$(d) $\frac{2g}{3}$

Answer 1

I think that this helps you

Answer 2

Answer:g/3

a= g sin /1+I/mr^2

Explanation:

g sin 30/1+mr^2/2*1/mr^2=. g*1/2/1+1/2= g/ 3