Question

A cylinder rolls on a horizontal plane surface. If the speed of the centre is 25 m/s, what is the speed of the highest point ?

Answer 1

As it is in rolling motion the velocity at the highest point will be the double of the velocity of the center of the rolling body.

Hence , the velocity will be 50m/s....

Answer 2

A cylinder rolls on a horizontal plane surface. If the speed of the centre is 25 m/s, The speed of the highest point is 50 m/2.

Explanation:

• The cylinder rolls with the centre velocity of 25 m/s. It is to be understood that the highest point’s velocity doubles with the rolling body’s centre velocity.
• The velocity’s age at its age is because of the rotation and its linear motion.
• It is to be seen that two velocities are same acting in the same direction. This is shown by the formula, $v=r \omega$.  
• This is calculated as $v=2 \times 25 \mathrm{m} / \mathrm{s}=50 \mathrm{m} / \mathrm{s}.$