Question

a cylinder tank 7m in diameter, contains water to a depth of 4m. Find the total area of the wet surface. (pi = 3.14)

Answer 1

Given : d = 7m , depth = 4 m

Wet area = CSA under water + area of base

Wet area = πdh + π(d/2)^2

= 3.14×7×4 + 3.14×(7/2)^2 cm^2

= 87.92 + 38.465 cm^2

= 126.385 cm^2

So, the total area of the wet surface

= 126.385 cm^2.

Answer 2

Answer:

Given:

A cylinder tank 7m in diameter, contains water to a depth of 4m.

To Find:

We need to find the total area of the wet surface.

Solution:

We have been given that the diameter of the cylindrical tank is 7m and its depth is 4m.

Inorder to find the wet area, we know

wet area = curved surface area under water + area of base

=> wet area = πdh + π(d/2)^2

= 3.14 × 7 × 4 + 3.14 × (7/2)^2 cm^2

= 3.14 × 28 + 3.14 × 49/4 cm^2

= 87.92 + 38.465 cm^2

= 126.385cm^2

Therefore the total area of the wet surface of the cylindrical tank is 126.385cm^2.