a cylinder tub of radius 5 cm and length 9.8 cm is full of water. a solid in the form of a right circular cone mounted on a hemisphere is immersed into tub. if the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm find volume of water left in the tub<br />plz ans quickly
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Answer:●volume of cylinder=T| r²h=22/7×5²×9.8=770cm³
●volume of hemisphere=2/3 T| r³=2/3×22/7×3.5²=89.83cm³
●volume of cone=1/3T| r²h=1/3×22/7×3.5²×5=6.41cm³
●total volume of solid=volume of cone+volume of hemisphere=89.83+6.41=96.24cm³
●now, total volume of water left in the cylinder=volume of cylinder-volume of solid=770-96.24=673.76cm³....
Explanation:note that T| is actually a pie....try to understand it.....hope it will help you:)
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