Question

a cylinder tub,whise diameter is 12 cm and height 15 is full of ice cream .the whole ice cream is to be divided into 10 children in equal ice cream cones with conical base sumounted by hemispherical top..if the height of conical portion is twice the diameter if base ,find the diameter of conical part of ice cream cone.

Answer 1

Diameter of the container = 12 cm



Thus, radius of the container = 6 cm



Height of the container = 15 cm

Volume of the container =πr2h=227×6×6×15=1697.143 cm3

Height of a cone = 12 cm
Diameter of a cone = 6 cm
Radius of a cone = 3 cm
Volume of a cone =13πr2h=13×227×3×3×12=113.143 cm3
Volume of hemisphere=23πr3=23×227×3×3×3=56.571 cm3

Volume of ice-cream in each cone = 113.143+56.571=169.714 cm3

Number of cones of required dimension that can be filled with the given ice-cream=1697.143/ / 169.714=10




$= = =$