a cylinder tube open at both ends is made of metal. the inner diameter of the tube is 10.4 cm and its length is 25cm the thickness of the metal is 8mm everywhere. calculate the volume of the metal in the cylinder
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volume of the metal of acylinder is pi r square h.Then
h-25cm
d-10.4cm
thickness- 8cm
outer diameter(D)- d+thickness
10.4+8= 18.4
pi value 22/7
r=10.4/2=5.2
R=18.4/2=9.2
2pih(R square- r square)
2*22/7(9.2-5.2)
2*22/7*4
h-25cm
d-10.4cm
thickness- 8cm
outer diameter(D)- d+thickness
10.4+8= 18.4
pi value 22/7
r=10.4/2=5.2
R=18.4/2=9.2
2pih(R square- r square)
2*22/7(9.2-5.2)
2*22/7*4
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