Question

A cylinder vessel open at the top has a base diameter 56 CM if the total cost of painting the outer curved surface of the vessel is Rs 352 at the rate of Rs 0.2 per 100 cm square then what is the height of the vessel of?

Answer 1

Answer-

The height of the vessel is 10m.

Solution-

If the total cost of painting the outer curved surface of the vessel is 352 rupees at the rate of 0.2 per 100 cm²

i.e 0.2 rupees is spent for painting 100 cm², so calculation for 252 will be give us the area.

Area of the curved surface will be

$=\frac{100\times 352}{0.2} =176,000\ cm^2$

The diameter of the cylindrical vessel = 56 cm, let us assume the height is h cm

Curved surface area of the cylinder is,

$\Rightarrow A=\pi \times d\times h$

Putting the values,

$\Rightarrow A=\pi \times 56\times h$

$\Rightarrow A=175.93h$

This two expression for the area will be the same,

$\Rightarrow 175.93h=176,000$

$\Rightarrow h=\frac{176,000}{175.93}=1000.39\approx 1000\ cm$

$\Rightarrow h=10\ m$

Therefore, the height of the vessel is 10m

Answer 2

Thank you so much for asking this question, here is your answer:

Curved Surface: = 2πrh

352 = 2 x 227 x 28 x h

352 = 44 x 4 x h

352 = 156 x h

352/156 = h

when we solve the above equation we will get this:

86/39 x 0.2 / 10 x 100

44.10 is the final answer for this question.

If there is any confusion please leave a comment below.