A cylinder vessel open at the top has a redius 10cm and height 14 cm .find the total surface area of the vessel .(takeπ=3.14)
sivaprasad2000:
Should I consider the area inside the vessel?
1193.2 cm sq answer this question, plss solve this question
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Answered by
2
See the formula of surface area of cylinder =2πrh+πr²
=2×3.14×10×14+3.14×10²
=62.8×14+314
=879.2+314
=1193.2cm2
This is the area of vessel
=2×3.14×10×14+3.14×10²
=62.8×14+314
=879.2+314
=1193.2cm2
This is the area of vessel
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Answered by
3
Total surface area = Area of cylinder + Area of circular base
= 2πrh + πr^2
= πr (2h + r)
= 3.14 * 10 [(2 * 14) + 10]
= 1193.2 sq.cm
= 2πrh + πr^2
= πr (2h + r)
= 3.14 * 10 [(2 * 14) + 10]
= 1193.2 sq.cm
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